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30w-w^2=81
We move all terms to the left:
30w-w^2-(81)=0
We add all the numbers together, and all the variables
-1w^2+30w-81=0
a = -1; b = 30; c = -81;
Δ = b2-4ac
Δ = 302-4·(-1)·(-81)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-24}{2*-1}=\frac{-54}{-2} =+27 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+24}{2*-1}=\frac{-6}{-2} =+3 $
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